google API погода

Discussion in 'PHP' started by Shkiper2009, 29 May 2011.

  1. Shkiper2009

    Shkiper2009 New Member

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    {
    echo '<div class="weatherIcon">';
    echo '<img src="http://www.google.com/' .$new->icon['data'] . '"/><br/>';
    echo '</div>';
    echo '<div class="textweather">';
    echo 'Cейчас: '.$new->temp_c['data'].'°C'.'<br/>';
    echo $new->condition['data']. '<br/>';
    echo ''.$new->humidity['data']. '<br/>';
    echo '</div>';
    }

    }
    echo '</div>';
    }
    getWeather();
    ?>

    что я в обработчике делаю не так подскажите ??
     
    #1 Shkiper2009, 29 May 2011
    Last edited: 31 May 2011
  2. Shkiper2009

    Shkiper2009 New Member

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    люди! как решить проблему?
     
  3. roxblnfk

    roxblnfk Elder - Старейшина

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    убери
    http://www.google.com/
     
  4. Shkiper2009

    Shkiper2009 New Member

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    е мае! точно! а я с кавычками убрал! спасибо